Disable YouTube number shortcuts

Stop the anoying 0 to 9 YouTube shortcuts from ruining your wathing experience while allowing all the other shortcuts to work

< 脚本 Disable YouTube number shortcuts 的反馈

提问 / 留言

§
发布于:2023-04-10

Hi, what about using isNaN instead of keys and keys.indexOf?

(function() {
    'use strict';

    (window.opera ? document.body : document).addEventListener('keydown', function(e) {
        if (isNaN(e.key) || e.isComposing || e.ctrlKey || e.altKey) return;
        e.cancelBubble = true;
        e.stopImmediatePropagation();
        return false;
    }, !window.opera);
})();
§
发布于:2023-04-10

I realised it also needs a e.key === ' ' condition

if (e.key === ' ' || isNaN(e.key) || e.isComposing || e.ctrlKey || e.altKey) return;`
§
发布于:2024-01-20

The source code is based on a very old stackoverflow post

Obviously this script is just created by newbie.

(function () {
    const keys = new Set('0123456789'.split(''));
    // keys.add(' '); // You can add other keys. Check in https://www.toptal.com/developers/keycode
    document.addEventListener('keydown', function (e) {
        if (keys.has(e.key) || e.isComposing || e.ctrlKey || e.altKey) return;
        e.stopPropagation();
        e.stopImmediatePropagation();
    }, true);
})();
§
发布于:2025-06-28
(function () {
    const keys = new Set('0123456789'.split(''));
    // keys.add(' '); // You can add other keys. Check in https://www.toptal.com/developers/keycode
    document.addEventListener('keydown', function (e) {
        if (keys.has(e.key) || e.isComposing || e.ctrlKey || e.altKey) return;
        e.stopPropagation();
        e.stopImmediatePropagation();
    }, true);
})();

Why not const keys = '0123456789' and keys.includes(e.key) instead?

§
发布于:2025-06-28
编辑于:2025-06-28

(function () {
const keys = new Set('0123456789'.split(''));
// keys.add(' '); // You can add other keys. Check in https://www.toptal.com/developers/keycode
document.addEventListener('keydown', function (e) {
if (keys.has(e.key) || e.isComposing || e.ctrlKey || e.altKey) return;
e.stopPropagation();
e.stopImmediatePropagation();
}, true);
})();
Why not const keys = '0123456789' and keys.includes(e.key) instead?

Yes it can.

But if you want to handle other keys as well, Set is a better choice.

If you want to test more keys, the keys string would be long and searching would be time consuming.

Set is O(1) which is fast.

For "0123456789" case, they should have no difference.

发布留言

登录(不可用)以发布留言。

长期地址
遇到问题?请前往 GitHub 提 Issues。